(3y^2)+3y=135

Solution for (3y^2)+3y=135 equation:

(3y^2)+3y=135

We move all terms to the left:

(3y^2)+3y-(135)=0

a = 3; b = 3; c = -135;
Δ = b2-4ac
Δ = 32-4·3·(-135)
Δ = 1629
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1629}=\sqrt{9*181}=\sqrt{9}*\sqrt{181}=3\sqrt{181}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{181}}{2*3}=\frac{-3-3\sqrt{181}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{181}}{2*3}=\frac{-3+3\sqrt{181}}{6}
$